$\text { (#) } n=m$: $=$ > 每年计息次数、贴现次数
$\text { (1) } d=i /(1+i)=i \cdot v=1-\left(1-\frac{d^{(n)}}{n}\right)^{n}$: $=$ >
$\text { (2) } i=d /(1-d)=\left(1+\frac{i^{(m)}}{m}\right)^{m}-1=\mathrm{e}^{\delta}-1$: $=$ >
$\text { (3) } v=1-d $: $=$ >
$\text { (4) } i-d=i d $: $=$
$\text { (5) } i^{(m)}=m\left[(1+i)^{1 / m}-1\right] $: $=$ >
$\text { (6) } d^{(n)}=n\left[1-(1-d)^{1 / n}\right]=n\left(1-v^{1 / n}\right) $: $=$ >
$\text { (7) }\left[1+\frac{i^{(m)}}{m}\right]^{m}=\left(1-\frac{d^{(n)}}{n}\right)^{-n} $: $=$
$\text { (8) } \delta=\ln (1+i)$: $=$ >

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% \f is defined as f(#1) using the macro \f{x} = \int_{-\infty}^\infty \hat \f\xi\,e^{2 \pi i \xi x} \,d\xi